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Therefore Work =

integral from 0 to Q of V(q) dq =

integral from 0 to Q of (1/C)q dq =

Q^2/2C =

1/2 CV^2=

1/2 VQ which consequently equals the potential energy stored in the capacitor

so my question overall is::

Why it is not negative 1/2 VQ for PE since PE is the negative of work?

Everywhere I look there is never a -PE=W but they immediately equate the two being PE=W. I think I am missing something very simple here.