PeroK said:
The uncertainty principle (UP) relates to the spread of measurements you would get if you made them. It's not about the precision of those measurements.
1) Wrong: the particle has a definite position, but the UP limits how precisely you can measure its position.
2) Correct: the particle has no definite position and the UP imposes a minimum "spread" or "variance" of measurements of position on an ensemble of identically prepared systems. (The variance in position measurements is inversely proportional to the variance in momentum measurements.)
Thank you Perok, explanations like this are exceptionally helpful.
Am I correct in thinking , with #2, that the minimum "spread"/"variance" of measurements imposed by the UP relates to the probabilistic predictions of QM? Is this directly related to the wavefunction of the particle? Is this what the wavefunction is?
PeroK said:
Warning: you will find a lot on line to the contrary.
Thank you for the heads up!
PeroK said:
The die analogy is of some use: every throw of the die represents a totally precise measurement. The measurement values are equally spread across 1-6. The expected value is actually 3.5 if you throw a die repeatedly. It's not the case that the die was "really 3.5" before you threw it, but you got imprecise measurements. The die is actually never 3.5, it's only ever 1-6 with complete precision after a throw.
Relating this analogy to realism, we might ask the question what was the die showing before the throw, or what was it showing before we measured it? To me it sounds like the standard interpretation says it is meaningless to talk about the die until after its been thrown and the measurement taken.
PeroK said:
Yes, but it is a "very different beast" from the UP as above.
I see. Thank you.
PeroK said:
I thought you might like the following. This is from one of the standard undergraduate QM textbooks, by Griffiths. This sort of thing is why I love his book. The underlines are mine:
Note first that every measurement of an electron spin about any axis always returns the same precise value ℏ/2ℏ/2. Except, the spin can be clockwise or anticlockwise, represented by ±ℏ/2±ℏ/2. Note that this is always 1/3 of the "total" spin. Unlike a classical object, you can never find an axis of spin rotation: and, of course, according to QM there is no axis of spin. Whatever axis you choose, you always get 1/3 of the total spin. If we measure spin about the z-axis, then we get ±ℏ/2±ℏ/2 and after the measurement the electron is said to be in the state z+z+ or z−z−, depending on the measurent value. Similary, if we measure spin about the x or y axes.
This is incredibly helpful Perok. Thank you!
Am I understanding correctly when I think that when we measure the spin of a particle, we are essentially measuring whether it is clockwise or anti-clockwise (is this the same as up and down?) along a given axis? Is this what the Stern-Gerlach does, it deflects the particle according to its orientation thereby allowing us to ascertain whether it was anti-clockwise or clockwise?
Is it the case that we can choose to measure along any of the 3 axes and we will get an answer of either clockwise or anti-clockwise?
PeroK said:
Let's say we start out with an electron in the state z+z+. If someone asks "what is the z-component of the electron's spin?", we could answer unambiguously +ℏ/2+ℏ/2. For a measurement of spin about the z-axis is certain to return that value. But, if our interrogator asks instead, "what is the x-component of the electron's spin?" we are obliged to equivocate. If you measure spin about the x-axis the chances are 50-50 that you will get either +ℏ/2+ℏ/2 or −ℏ/2−ℏ/2. If the questioner is a "realist" he will regard this as an inadequate - not to say impertinent - response. "Are you telling me you don't know the true state of that particle?" On the contrary, we know precisely that the state of that particle is z+z+. "Well then, how come you can't tell me what the x-component of its spin is?" Because it simply does not have a particular x-component of spin. Indeed it cannot, for if both the z-spin and x-spin were well-defined, the UP would be violated.
Just trying to parse this. Is it the case that we can prepare an electron in the state z+z+, which is why we can unambiguously answer that it's z-component is +ℏ/2+ℏ/2? Or, do we have this unambiguous answer only after we measure the particle? The above seems to suggest that we can prepare it in the z+z+ state.
Let's say someone prepares the particle but doesn't tell us what it is. Am I correct in saying that if we measure spin about the x-axis, we will calculate the chances as being 50-50 that we will get either +ℏ/2+ℏ/2 or −ℏ/2−ℏ/2, with the same 50-50 chance if we chose either of the other two axes?
PeroK said:
At this point our challenger grabs the test tube and measures the x-component of spin. Let's say he gets +ℏ/2+ℏ/2. "Aha!" (he shouts in triumph), "this particle has a perfectly well-defined value of x-spin." Well, it does now, but that doesn't prove it had that value prior to your measurement. "What has happened to your UP? I now know both the z-spin and the x-spin." But you do not: your measurement altered the particle's state; it is now in the state x+x+, and you no longer know the value of its z-spin. Check it out: measure the z-spin. If we repeat this scenario over and over, for the measurement of z-spin we will get +ℏ/2+ℏ/2 or −ℏ/2−ℏ/2 with equal probability.
To the layman, philosopher or realist, a statement of the form "this particle does not have a well-defined position or momentum or spin or whatever) sounds vague, incompetent or (worst of all) profound. It is none of these. But, its precise meaning , I think, is almost impossible to convey to anyone who has not studied QM in some depth.
Electron spin is the simplest and cleanest context for thinking through the conceptual paradoxes of QM.
Again, thank you Perok, I feel like this helps to clarify a lot. Personally don't think that the idea that "a particle does not have a well-defined position or momentum or spin or whatever" is all that vague. I think the trade-off between the pieces of information makes sense. I would think that in order to be exact about the position of a particle you would need to stop it dead. In so doing you clearly kill its momentum and so lose that information. I do have trouble reconciling some of the statements that are sometimes made in relation to the UP, some of which you have mentioned yourself. I have emboldened them above and it might bring some clarity to outline where my conflict lies.
Even if my characterization of the UP above isn't exactly accurate, we can simply work from the notion of the particle having a
well defined z-spin; as you mentioned we can start with a particle in the z+z+ or z- z- state with precise values of ±ℏ/2±ℏ/2. If we take this as our definition of
well defined, then we can see that it presupposes that the spin component must have an assigned value. But, how can it have an assigned value without making a measurement? Measurement is essentially the process by which we assign values.
Just taking out the emboldened statements, I will try to outline my reasoning and if you feel so inclined you can highlight where I am going wrong:
In your example above of the person choosing to measure the x-spin of the particle and the precise value is returned, you state that
that doesn't prove it had that value prior to your measurement. This is somewhat of a tautology, because measurement is the process by which we assign values. You make a somewhat different, but more definitive statement before that: i
t simply does not have a particular x-component of spin.
There is a distinction to be made here between saying that the particle didn't have a particular
value for spin (in the given direction) prior to measurement and saying that it simply does not have a
particular component of spin (in that direction).
Measuring the precise x-spin value of the particle doesn't prove that it had that value prior to measurement because it is meaningless to talk about
values prior to measurement. It is also true to say that measuring the x-spin value doesn't prove that it had an x-component of spin either but - here is the point of contention - it equally doesn't prove that it didn't have an x-component of spin prior to measurement. It is possible that it did have an x-component.
The UP - as far as I understand it - tells us that both the z-spin and the x-spin can't be well defined because to be well defined implies having precise values, which itself implies measurement. The UP specifies the trade-off between measuring the two spin components. However, measuring the spin in the z direction doesn't allow us to conclude that i
t simply does not have a particular x-component of spin. It may well have an x-component, we cannot be certain that it does or doesn't
To say that the particle simply
does not have a particular x-component of spin would, to my mind, violate the UP because it seems to be a pretty definitive, pretty certain statement about the x-component of the spin of the particle. How do we know that it doesn't have an x-component?
PeroK said:
(Note: that is to say after the measurement of x-spin, we no longer know the z-spin, which has become "uncertain".)
This is an example of the point. The z-spin has become "uncertain" but that doesn't mean that we can say with certainty that it simply
does not have a particular z-component of spin
.Hopefully the error in my reasoning is easily identifiable there.