How Is the Elevator's Acceleration Calculated Using Newton's Second Law?

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SUMMARY

The acceleration of a 1000 kg elevator held by two cables exerting 6000 N each can be calculated using Newton's Second Law. The net force (FNET) acting on the elevator is determined by the equation FNET = (6000 N + 6000 N) - Fg, where Fg is the gravitational force. The gravitational force is calculated as Fg = mg, resulting in Fg = 1000 kg * 9.81 m/s² = 9810 N. The final calculation yields an acceleration of approximately 2.2 m/s².

PREREQUISITES
  • Understanding of Newton's Second Law (FNET = ma)
  • Knowledge of gravitational force calculation (Fg = mg)
  • Ability to construct and interpret force diagrams
  • Basic algebra for solving equations
NEXT STEPS
  • Study advanced applications of Newton's Laws in different contexts
  • Learn about free body diagrams and their significance in physics
  • Explore the effects of varying mass and force on acceleration
  • Investigate real-world applications of elevator mechanics and safety systems
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for practical examples of Newton's Second Law in action.

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Homework Statement



A 1000 kg elevator is held up by two cables. If each able exerts a force of 6000N upwards upon the elevator, find the elevator's acceleration.

Homework Equations



Fg=mg

FNET=ma

The Attempt at a Solution



I started with a force diagram to help me and then I think I'm supposed to use the FNET=ma formula. So I plugged in the variables as follows: (6000+6000)-Fge=1000a
How do you solve for acceleration in this problem when I also need to find the Force that gravity exerts on the elevator (Fge)?

Would the answer be 2.2m/s^2?
 
Last edited:
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Fge would simply be the weight, mg, of the elevator.
 

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