How Is the Formula PEcos(θ) Derived for Dipoles in a Constant Electric Field?

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The potential energy of a dipole in a constant electric field is expressed as P·E = PEcos(θ). This relationship can be derived by considering two charges of equal magnitude and opposite sign, where the total potential energy in a homogeneous electric field is V = -Q r₀ · E. As the distance r₀ approaches zero, the dipole moment is defined as P = Q r₀, leading to the expression V = -P · E. This derivation clarifies the connection between dipole moment and potential energy in an electric field. Understanding this concept is essential for grasping the behavior of dipoles in physics.
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I know that the potential energy of a dipole in a constant electric field is

P(dot)E=PEcos(θ), but I can't seem to find how they got here; its not in my textbook.

If anyone knows why please tell me.
 
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A straight-forward way is to just use two charges of the same magnitude Q and opposite sign located at the origin and at \vec{r}_0 (negative charge in the origin). The total potential energy of this charge distribution in the homogeneous electric field is
V=-Q \vec{r}_0 \cdot \vec{E}.
Now the dipole moment is given for the limit \vec{r}_0 \rightarrow 0 such that Q \vec{r}_0=\vec{P}=\text{const}. This leads to
V=-\vec{P} \cdot \vec{E}.
QED.
 
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