How Is the Mass of a Block Determined When It Compresses a Spring?

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SUMMARY

The mass of a block that compresses a spring can be determined using the equation for energy conservation: 0.5mv² = 0.5kx². In this scenario, the spring constant (k) is 31 N/m, the block's speed (v) before impact is 3.5 m/s, and the compression distance (x) is 0.11 m. By correctly applying the equation and squaring the values, the mass can be calculated accurately.

PREREQUISITES
  • Understanding of energy conservation principles in physics
  • Familiarity with spring mechanics and Hooke's Law
  • Basic algebra skills for manipulating equations
  • Knowledge of units of measurement (N/m, m/s, kg)
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  • Review the principles of energy conservation in mechanical systems
  • Study Hooke's Law and its applications in spring mechanics
  • Practice solving problems involving kinetic and potential energy
  • Explore advanced topics in oscillatory motion and damping
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of energy conservation in spring systems.

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Homework Statement


A block is dropped onto a spring with k = 31 N/m. The block has a speed of 3.5 m/s just before it strikes the spring. If the spring compresses an amount 0.11 m before bringing the block to rest, what is the mass of the block?



Homework Equations


0.5mv^2=0.5kx^2


The Attempt at a Solution

0.5m3.5=0.5*31*.11
 
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Looks like you forgot to square the 3.5 and the .11.
 

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