How Is the ROC Right of the Rightmost Pole When There's a Pole at -2?

Thread starter reddvoid
Start date Sep 30, 2011
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Laplace Laplace transform Transform

AI Thread Summary

The discussion centers on the region of convergence (ROC) for a right-sided signal, questioning how the ROC can be defined as Re(s) > -3 when there is a pole at -2. Participants agree that the ROC should logically be Re(s) > -2, indicating a potential typo in the source material. The consensus is that the ROC must be to the right of the rightmost pole, which in this case is at -2. This discrepancy raises concerns about the accuracy of the information provided in the book. Overall, the participants conclude that the ROC should indeed be adjusted to reflect the pole's position.

Sep 30, 2011

reddvoid

in this question x(t) is right sided signal
so ROC should be to the right of right most pole
but here they've given ROC is Re(s) >-3
but there is a pole @ -2

attachment.php?attachmentid=39435&stc=1&d=1317394829.jpg

how is this ?

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Sep 30, 2011

uart

Science Advisor

Yes I also think that the ROC should be Re(s)>-2. Looks like the book has a typo.

Oct 4, 2011

reddvoid

Yes .
I think so

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