How Is the Time Constant Calculated in a Series-Parallel RC Circuit?

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 3K views
newyorkcity
Messages
28
Reaction score
0

Homework Statement



What is the time constant of the circuit shown in the figure? Each resistor has resistance R, and each capacitor has capacitance C. Internal resistance of the battery is negligible.

See the attached figure.


Homework Equations



tau=RC


The Attempt at a Solution



I assume that the R term has a coefficient of 5, due to the 5 resistors in series each with resistance R. I am confused about the capacitors. Since they are parallel, I assume that I can convert to the equivalent capacitor:

Ctotal=C1+C2+C3+C4+C5

resulting capacitance is 5C. So with terms of 5R and 5C, I get:

tau=25RC

am I on the right track?
 

Attachments

  • rc_circuit.png
    rc_circuit.png
    2.8 KB · Views: 442
Physics news on Phys.org
That's correct :smile:
 
thanks for your help guys, much appreciated.