How Is Thermodynamic Temperature Calculated for a Gas at the Triple Point?

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SUMMARY

The discussion focuses on calculating the thermodynamic temperature of a gas at its triple point using the equation T = LIMPTP→0 P/PTP * 273.16. The user calculated an average value of P/PTP as 1.53555 but encountered confusion regarding an additional step involving a factor of 2.5 in the solution. Another participant suggested a simpler method by evaluating P/Ptp to five decimal places, noting a consistent increment with each decrement of 250 mmHg in Ptp, facilitating a straightforward extrapolation to zero pressure.

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stockill92
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Hello, new to these forums

I'm trying to complete a basic thermodynamics problem, calculating the thermodynamic temperature of a gas immersed in water at triple point.

The problem begins with a table of pressures at varying temperatures of a gas under pressure P, and pressure P(tp) - triple point pressure.

wABiZ38.png


Now, I know the following equation;

T=LIMPTP→0P/PTP * 273.16

So I have calculated the average value of P/PTP as 1.53555

But I also have access to a solution to this problem, and in the solution an extra step is also taken:

dpQQSse.png


I don't understand the source of the 2.5 * avg change between P and P(tp). Where has this come from? Why is it necessary?

Thanks
 
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I don't understand either, but rather than trying to do so, I've used a more straightforward method. I evaluated P/Ptp to 5 decimal places for each of the five pairs of readings. It was then clear that the ratio increased by almost the same increment for each 250 mmHg decrement in Ptp. Hence naïve extrapolation of P/Ptp to zero pressure is very straightforward.
 

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