How is Torque Calculated in a Rotation Lab?

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SUMMARY

The discussion centers on calculating torque in a rotation lab scenario, specifically using the equation T = 2g * 20, where 'g' represents gravitational acceleration at 9.8 m/s². A participant questions the professor's assertion that the torque is clockwise, given a 2 kg mass positioned 20 cm from the fulcrum. The correct interpretation of torque involves understanding the lever arm and the direction of the applied force, which in this case, indicates a downward motion on the right side of the fulcrum, confirming a clockwise rotation.

PREREQUISITES
  • Understanding of torque calculations
  • Familiarity with gravitational acceleration (g = 9.8 m/s²)
  • Knowledge of lever arms and fulcrum mechanics
  • Basic physics concepts related to equilibrium and rotation
NEXT STEPS
  • Study the principles of torque and rotational equilibrium
  • Learn how to apply the torque equation T = r × F in various scenarios
  • Explore the effects of different mass placements on torque direction
  • Investigate the implications of lever arm length on torque calculations
USEFUL FOR

Students in physics courses, educators teaching mechanics, and anyone interested in understanding the principles of torque and rotational dynamics.

Yoli123
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Homework Statement
For each meter stick on fulcrum with attached masses (equilibrium/no equilibrium) find torque and rotation
Relevant Equations
equilibrium for rotation
So for the first one on the left is it T= 2g*20=40Nm ? Our professor said it is clockwise I just don't understand how she gets that conclusion.
 

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Yoli123 said:
Homework Statement:: For each meter stick on fulcrum with attached masses (equilibrium/no equilibrium) find torque and rotation
Relevant Equations:: equilibrium for rotation

So for the first one on the left is it T= 2g*20=40Nm ? Our professor said it is clockwise I just don't understand how she gets that conclusion.
Welcome to PhysicsForums. :smile:

Can you please post a PDF version of the document? It's can be dangerous to open a Word document. You can use PrimoPDF or any other free PDF writer. Thanks.

And what does this mean? "T= 2g*20=40Nm"

g is not a force, and you had a lever arm of 20 meters?
 
Last edited:
Yoli123 said:
So for the first one on the left is it T= 2g*20=40Nm ? Our professor said it is clockwise I just don't understand how she gets that conclusion.
I couldn't find in the attachment where the units of mass are stated. I assume they are kg. So you have a 2kg mass attached at 20cm from the fulcrum. g is given as 9.8m/s2. Paying careful attention to units, what does that give for the torque?
The mass is attached to the right of the fulcrum, so that side should go down. Seems like clockwise to me.
 

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