How Is Total Pressure Calculated in Water?

[NooDota]

Homework Statement

Assuming g = 10 ms^-2 and the volumetric mass for water is 10^3 kg.m^-3 and the air pressure is 10^5 Pa, the total pressure on a point inside the water that's in equilibrium with a distance of 2m from its free surface is:

A. 0.8 * 10^5

B. 1.002 * 10^5

C. 1.2 * 10^5

D. 1.02 * 10^5

Homework Equations

The Attempt at a Solution

What I did was apply: Pnet = Pair + ρ*g*h

Pnet = 10^5 + 10^3 * 10 * 2

Pnet = 10^5 + 10^4 *2What am I doing wrong?

 

[RUber]

Why do you think you are doing something wrong?

 

[NooDota]

Oh nevermind, lock this.

I never bothered to actually calculate how much is 10^5 + 10^4 * 2

 

[brainpushups]

Try writing your answer in proper scientific notation...

 

[RUber]