How Is Work Calculated in a Forced Oscillation with Resistance During Resonance?

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SUMMARY

The calculation of work produced by the resistance force in a forced oscillation during resonance involves integrating the product of force and velocity over one period. The resistance force is defined as Fres = -bv, where b is the damping constant, and the external force is given by Fext = Fmax cos(ωt). To find the work done, the integral W = ∫0T F(t)v(t) dt must be evaluated, using the relationship P = Fv for power. This approach allows for accurate calculation of work in non-constant force scenarios.

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Homework Statement


How can I calculate the work which is produced by the resistance force in a forced oscillation in one period?
The only forces on the oscillatory body are the resistance force and the external force.
The oscillatory body is in resonance.

Homework Equations


resistance force: F_{res}=-bv (b is the damping constant)
external force:F_{ext}= F_{max} \cbullet \cos\omega t
x=Asin\omega t
u=u_{max}cos\omega tThanks in advance
 
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How can you calculate work in general?

ehild
 
the work in a constant force is: W=F*d.
Moreover the work can be calculated from the area from graph F-d.

I can't find the work with either ways.
 
A definition of work can be found in this http://en.wikipedia.org/wiki/Work_(physics)" .
 
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bour1992 said:
the work in a constant force is: W=F*d.
Moreover the work can be calculated from the area from graph F-d.

I can't find the work with either ways.

The work is not constant here, and the area can be calculated as integral of force with respect to the displacement.

There is an other way to get work, by integrating power with respect to time for a given time period. And power (P) is the scalar product of force (F) and velocity (v). In case of one-dimensional motion,

P=Fv, and work done in one period is

<br /> W=\int_0^T{F(t)v(t)dt}<br />

You know that F =-bv, and v(t)=v_{max}cos(\omega t). Write the product of them and integrate.

ehild
 

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