How Long and Fast Does a Diesel Train Accelerate to Cover 6km?

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A diesel train accelerates uniformly from rest to 60 km/h in 6 minutes, covering 3 km during this period. The acceleration is calculated to be 600 km/h². After reaching its maximum speed, the train has 3 km remaining to travel at a constant speed. This additional distance takes 3 minutes to cover. Therefore, the total time taken for the journey is 9 minutes.
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Homework Statement



A deisel train accelerates uniformly from rest to reach 60km/hr in 6 minutes, after which the speed remains constant.
Calculate the total time taken to travel 6km and the acceleration.

Homework Equations


s= ut
v= u+at
s=ut + 0.5*at^2

The Attempt at a Solution


I'm not sure how to incorporate the accelaration part into the question.
I tried t=(v-u)/a but idon't know what to put in for the acceleration.
 
Last edited:
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That is not a question.
 
yeah i accidentally entered the post before i finished it, it's finished now.
 
Well the time taken to accelerate is 6min, because we are given that.

First find the distance traveled in the 6mins it is accelerating.

6mins = 1/10 hours. We must find the acceleration.

Re-arrange v= u+at for acceleration:

a = (v - u)/t = 60/(1/10) = 600 km/h^2

Now find the distance it travels:

s=ut + 0.5*at^2 = 0 + 0.5*600*(1/10)^2 = 3km

Therefore the train still has 3km left to go, but now it is traveling at a constant 60km/h, so the time taken is:

s = ut
so:
t = s/u = 3/60 = 1/20 of an hour = 3mins

So the total time for the journey is 9mins
 
thank you
 
My Pleasure.
 
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