How Long Does It Take a Comet to Travel 80 Degrees Around the Sun?

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SUMMARY

The discussion centers on calculating the time it takes for a comet to travel 80 degrees around its elliptical orbit around the Sun. Given the closest approach distance of R = 6 * 10^8 m and a speed of 8 * 10^5 m/sec, the angular velocity (omega) is determined to be 1/750 radians per second. By integrating omega and setting it equal to 80 degrees (or 4/9 pi radians), the time calculated for the comet to travel this distance is approximately 1047.2 seconds. The discussion highlights the importance of recognizing that the comet's orbit is elliptical rather than circular.

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Homework Statement


A comet passes the sun at a distance of closest approach R = 6 * 10^8 m and speed 8 * 10^5 m/sec. How long will it take to travel 80 degrees around its orbit from the point of closest approach.


Homework Equations


omega = velocity / radius


The Attempt at a Solution


Since we can get omega from the above information, I should only have to integrate omega and set that equal to 80 degrees (or 4/9 pi radians)
omega = 8 * 10^5 / (6 * 10^8) or 1/750
the integral of this makes 1/750t and set that equal to 4/9 pi radians so,

t = (750 * 4 * pi)/9
t = 1047.2 seconds

I am not sure if this is the proper way of writing this equation and confirmation would be appreciated. Thanks in advance.
 
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Hi Mastablade! :smile:

(have an omega: ω and a pi: π :wink:)

No, that's for a circular orbit.

A comet goes round the sun in a very elongated ellipse.
 

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