How Long Does It Take a Dropped Object to Hit the Ground from a Rising Balloon?

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A balloon ascends at 12 m/s from a height of 81 m, and a 2 kg object is dropped from it. The calculation involves using the equation of motion, s = ut + 1/2 at^2, where the initial velocity is +12 m/s (upward) and acceleration due to gravity is -10 m/s² (downward). The correct approach requires consistent directionality in signs, leading to a revised equation that accounts for the balloon's upward motion. The initial attempt resulted in an incorrect time of 42 seconds, indicating a need for careful reevaluation of the calculations.
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Homework Statement



A balloon is at a height of 81 m is ascending upward with a velocity of 12 ms1. A body of 2 kg weight is dropped from it. If g = 10 ms2, the body will reach the surface of Earth in what time.


Homework Equations





The Attempt at a Solution



I don't think mass is of any importance in this question. Hence, I tried to solve it this way:

Since initial velocity = -u
(s=ut+1/2at^2)

81 = -12t+1/2*10*t^2
Solving, we have t = 42seconds.

However this is not the answer. Please explain how I solve this question.
Thanks in advance
 
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Hello physics kiddy,

physics kiddy said:

Homework Statement



A balloon is at a height of 81 m is ascending upward with a velocity of 12 ms1. A body of 2 kg weight is dropped from it. If g = 10 ms2, the body will reach the surface of Earth in what time.


Homework Equations





The Attempt at a Solution



I don't think mass is of any importance in this question. Hence, I tried to solve it this way:

Since initial velocity = -u
(s=ut+1/2at^2)

81 = -12t+1/2*10*t^2
Solving, we have t = 42seconds.

However this is not the answer. Please explain how I solve this question.
Thanks in advance

I think your signs are messing you up. You can orient your coordinate system however you want, it's up to you. But you have to pick a direction and stick to it consistently. In this case, let's choose upward to be the positive direction, and downward to be the negative direction. Then, the object's initial velocity (when dropped) is *upward*, because it is ascending along with the balloon at +12 m/s.
 
I have assumed upward to be negative and downward positive to make things easier, however, I am not getting the answer...
 
physics kiddy said:
I have assumed upward to be negative and downward positive to make things easier, however, I am not getting the answer...

Can you show the steps of your solution in more detail?
 
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