The discussion focuses on calculating the time a ball remains in the air after being thrown vertically upward with an initial speed of 11.0 m/s from a height of 1.50 m. Using the kinematic equation for vertical motion, the total time in the air can be determined by considering the upward motion until the ball reaches its peak and the subsequent downward motion until it hits the ground. The acceleration due to gravity (g) is taken as 9.81 m/s². The final calculation reveals that the ball stays in the air for approximately 2.26 seconds before hitting the ground.
PREREQUISITESStudents in physics, educators teaching kinematics, and anyone interested in understanding the principles of projectile motion and time of flight calculations.
Can you express y in terms of initial position, velocity, acceleration (g) and time? y = y0 + ___ +- _____bommer said:A student standing on the ground throws a ball straight up. The ball leaves the student's hand with a speed of 11.0 m/s when the hand is 1.50 m above the ground
How long is the ball in the air before it hits the ground? (The student moves her hand out of the way.)