How long is this area in the air?

[shawn2004]

I understand what they are asking me in these problem but I don't know how plug these numbers in the equations.
If you could help me it would be wonderful thanks.
Fc if spun on a 2.5m string at 6 radians every 10 seconds?An arrow is shot at 20 m/s at an angle from the horizontal of 37 degree.what its maximum height? time in the air?Horitzontal range

tangential velociy if rotational frequency=0.75 Hz with a readius of 4.0m

Angular accerlation if change from 10rad/pie to stopped in 3.0 seconds?

 

[Feldoh]

I understand what they are asking me in these problem but I don't know how plug these numbers in the equations.
If you could help me it would be wonderful thanks.
Fc if spun on a 2.5m string at 6 radians every 10 seconds?


An arrow is shot at 20 m/s at an angle from the horizontal of 37 degree.what its maximum height? time in the air?Horitzontal range

tangential velociy if rotational frequency=0.75 Hz with a readius of 4.0m

Angular accerlation if change from 10rad/pie to stopped in 3.0 seconds?

Um, no offense but I don't really understand anything you just said, could you make it a bit more clear?

 

[ogb p]

I would first clarify what type of motion is being described in each scenario. For the first problem, it appears to be describing circular motion, so I would use equations related to circular motion such as centripetal force and angular velocity. For the second problem, it seems to be describing projectile motion, so I would use equations related to projectile motion such as initial velocity, angle, and acceleration due to gravity.

To answer the first question about the length of time in the air, I would need to use the equation for angular velocity (ω = Δθ/Δt) and solve for time (Δt). In this case, the initial angle is 6 radians and the time is 10 seconds, so the time in the air would be 10 seconds.

For the second problem, to find the maximum height, I would use the equation for projectile motion (h = (v^2 * sin^2θ)/2g) where v is the initial velocity (20 m/s), θ is the angle (37 degrees), and g is the acceleration due to gravity (9.8 m/s^2). To find the time in the air, I would use the equation (t = 2v * sinθ/g) where v is the initial velocity and θ is the angle. To find the horizontal range, I would use the equation (R = v^2 * sin2θ/g).

For the last problem, to find the angular acceleration, I would use the equation (α = Δω/Δt) where Δω is the change in angular velocity (from 10 rad/π to 0) and Δt is the change in time (3 seconds).