How long will it take to overtake

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SUMMARY

The discussion focuses on the overtaking scenario between two cars, where the car behind travels at 100 km/h and the car in front at 95 km/h. Given the lengths of the cars (4.73 meters) and the gap between them (55.57 meters), the car behind must gain a total of 110 meters to complete the overtaking maneuver. The calculations reveal that the faster car will take 22 seconds to overtake, covering 660 meters in that time, confirming that it can overtake within a distance of 2.1 km.

PREREQUISITES
  • Understanding of basic physics concepts related to speed and distance
  • Ability to convert units (km/h to m/s)
  • Familiarity with equations of motion for constant speed
  • Knowledge of how to calculate relative speed between two moving objects
NEXT STEPS
  • Learn how to convert speeds from km/h to m/s accurately
  • Study the equations of motion for constant velocity scenarios
  • Explore relative motion concepts in physics
  • Practice similar overtaking problems with varying speeds and distances
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This discussion is beneficial for physics students, educators, and anyone interested in understanding motion dynamics, particularly in scenarios involving overtaking vehicles on the road.

joseph0205
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there a two cars, the one behind is traveling at 100km/hr, the one in front is traveling at 95 km/hr. say the car lengths are 4.73 metres and between the two cars is 55.57 metres. no acceleration for either cars.

will the car at the back be able to over take the other car within 2.1km?

could you also please show the equation you used, its for a physics assignment due monday thanks :)
 
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joseph0205 said:
there a two cars, the one behind is traveling at 100km/hr, the one in front is traveling at 95 km/hr. say the car lengths are 4.73 metres and between the two cars is 55.57 metres. no acceleration for either cars.

will the car at the back be able to over take the other car within 2.1km?

could you also please show the equation you used, its for a physics assignment due monday thanks :)

I will explain with simpler numbers - you can repeat with the real values.

Make the cars 5m long, and the gap between them 50m

I am assuming that at first, the front of the fast car is 50m from the back of the slow car.
After overtaking, then moving back to his lane when the gap is again 50m, we now have the front of the fast car 60m in front of the slow car [so that the rear of the fast car is 50m in front of the slow car.
That means the fast car has to gain 110m

Convert those speeds to m/s and you get something like 25m/s and 30m/s [you can use the real numbers remember]
That means the fast car is gaining 5m each second.
To move up the 110 m that would take 22 seconds.

At 30m/s, the fast car will cover 660m in that time.

I chose easy numbers to use for explanation purposes. You need to use the real numbers in a similar way to see how far the cars travel during this manoeuvre.
 

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