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Vodkacannon

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Imagine a person is moving at the equator in the direction opposite of the Earth's spin.

Assume:

the person's "weight" = 90.718 kg,

they person's speed = 1m/s,

The Earth's "weight" = 5.972*10^24 kg,

the angular velocity of the Earth = 7.292*10^-7 rad/s,

The radius of the Earth = 6.371*10^6 m,

and the inertia of the Earth = 8*10^37 kgm^2

**How long would it take them to stop the rotation of the Earth?**Assume:

the person's "weight" = 90.718 kg,

they person's speed = 1m/s,

The Earth's "weight" = 5.972*10^24 kg,

the angular velocity of the Earth = 7.292*10^-7 rad/s,

The radius of the Earth = 6.371*10^6 m,

and the inertia of the Earth = 8*10^37 kgm^2

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