- #1
hello95
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So I just got out of my linear algebra midterm, and this question is confusing the hell out of me. Basically, it's a subspace of R^4, such that the coordinates satisfy the following qualifications:
(a, b - a, b, 2(b - a))
So basically, a and b can range over the xz plane, and y and w sort of follow suit. I said that this space had the basis given by the three vectors:
(a,0,0,0)
(0,0,b,0)
(0,b-a,0,2(b-a))
But now that I look back at it, the more it seems like this is a 2-dimensional subspace, since you're essentially mapping from the xz plane to a line in yw, which means that it's basically isomorphic to a plane in three space.
Any thoughts?
(a, b - a, b, 2(b - a))
So basically, a and b can range over the xz plane, and y and w sort of follow suit. I said that this space had the basis given by the three vectors:
(a,0,0,0)
(0,0,b,0)
(0,b-a,0,2(b-a))
But now that I look back at it, the more it seems like this is a 2-dimensional subspace, since you're essentially mapping from the xz plane to a line in yw, which means that it's basically isomorphic to a plane in three space.
Any thoughts?