How many distinct L-structures can be constructed using this method?

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Homework Help Overview

The discussion revolves around the number of distinct L-structures that can be constructed using a fixed signature L and a finite set X as the domain. Participants are exploring the implications of the definitions and interpretations of symbols within the context of model theory.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to understand how distinct L-structures can be formed when they share the same set of constants, relations, and functions. There are questions about the interpretation of symbols and the relationship between the finiteness of X and the number of interpretations possible for the symbols in the language.

Discussion Status

Some participants have provided examples to illustrate how distinct L-structures can exist despite having the same symbols. There is an ongoing exploration of the definitions and implications of language and structure in model theory, with some expressing confusion and seeking clarification.

Contextual Notes

Participants are new to model theory and are grappling with foundational concepts such as the meaning of language and the interpretation of relation symbols. There are indications of varying levels of understanding and familiarity with the subject matter.

bedi
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Let X be a set and L a signature; write k(X,L) for the number of distinct L-structures which have domain X. Show that if X is a finite set then k(X,L) is either finite or at least 2^w (w stands for omega).

Attempt: as L is fixed, all L-structures have the same n-ary relation and function symbols and the same set of constants. Although the symbols can be different, they represent the same function or relation or set so I can't use that fact to construct distinct L-structures. How can I even find 2 distinct L-structures when they have the same set of constants, relations and functions? Perhaps I should consider the complement of the set of constants. But their domain is X...
 
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bedi said:
Let X be a set and L a signature; write k(X,L) for the number of distinct L-structures which have domain X. Show that if X is a finite set then k(X,L) is either finite or at least 2^w (w stands for omega).
You mean "at most", don't you?

Attempt: as L is fixed, all L-structures have the same n-ary relation and function symbols and the same set of constants. Although the symbols can be different, they represent the same function or relation or set so I can't use that fact to construct distinct L-structures. How can I even find 2 distinct L-structures when they have the same set of constants, relations and functions? Perhaps I should consider the complement of the set of constants. But their domain is X...
 
That was my first thought too, but the book says "at least". It must be a misprint...
 
bedi said:
Although the symbols can be different, they represent the same function or relation or set so I can't use that fact to construct distinct L-structures.

I'm not sure what you mean here. The function symbols and relation symbols in the language have no meaning until they are interpreted in the structure.

The point of the exercise is to determine the number of different ways that the symbols of the language can be interpreted for a finite set; how many different n-ary functions can there be on a finite set and how many ways can there be to interpret an n-ary relation symbol.

The case distinction (finite vs. 2^w) is about the size of the language.

From what I can tell "at least" is not a typo.
 
I don't know what does "language" mean yet and could you give more hints? I couldn't figure out the relation between the finiteness of X and the number of different ways that the symbols of the language can be interpreted. I've started studying model theory yesterday...
 
bedi said:
How can I even find 2 distinct L-structures when they have the same set of constants, relations and functions?

Let L=\{R\}, i.e. the language consisting of a single unary relation symbol, and let X be any set.

Let \mathcal{A}=\{X,R^{\mathcal{A}}\} be the L-structure with R^{\mathcal{A}}=X.

Let \mathcal{B}=\{X,R^{\mathcal{B}}\} be the L-structure with R^{\mathcal{B}}=\emptyset.

Then \mathcal{A} and \mathcal{B} are both L-structures with universe X and \mathcal{A}\neq\mathcal{B}
 
gopher_p said:
Let \mathcal{A}=\{X,R^{\mathcal{A}}\} be the L-structure with R^{\mathcal{A}}=X.

Let \mathcal{B}=\{X,R^{\mathcal{B}}\} be the L-structure with R^{\mathcal{B}}=\emptyset.

Why R^A is not equal to R^B?
Edit: Dumbest question. Okay I understand it now, thank you.
 
To conclude: When R is in a language, it is "meaningless" until we define it as, say, R^A on an L-structure A. Correct?
 
bedi said:
I don't know what does "language" mean yet

Sorry. "Language" and "signature" are the same thing.

I couldn't figure out the relation between the finiteness of X and the number of different ways that the symbols of the language can be interpreted. I've started studying model theory yesterday...

Just focusing on relation symbols for a second ...

It appears like you're comfortable with the notion that the interpretation of an n-ary relation symbol in a particular structure is a subset of the nth Cartesian product of the universe of the structure. So for our signature L from above with the unary relation symbol R, the interpretation R^{\mathcal{C}} of R in the structure \mathcal{C}=\{X,R^{\mathcal{C}}\} can be any subset of X.

So the number of L-structures with universe X is the same as the number of subsets of X. If X is finite, then ...
 
  • #10
bedi said:
To conclude: When R is in a language, it is "meaningless" until we define it as, say, R^A on an L-structure A. Correct?

Yes.
 
  • #11
bedi said:
I've started studying model theory yesterday...

Don't expect to really understand this crap right away. It can be very confusing at first.
 
  • #12
Aha! At first I didn't think seriously about subsets because I thought that would contradict the fact that |dom(X)|=|X|, that is, if I choose a smaller set than X with dom(X)... But everything is clear with relations now.
 
  • #13
gopher_p said:
So for our signature L from above with the unary relation symbol R, the interpretation R^{\mathcal{C}} of R in the structure \mathcal{C}=\{X,R^{\mathcal{C}}\} can be any subset of X.

This is poorly worded. I should have said something like ...

For every U\subset X there is an L-structure \mathcal{C}_U=\{X,R^{\mathcal{C}_U}\} with R^{\mathcal{C}_U}=U.

The point being, given a structure \mathcal{C}=\{X,R^{\mathcal{C}}\}, R^{\mathcal{C}} is already interpreted (i.e. the structure has been given). We can't just choose any subset after the fact.
 

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