How Many Electrons Are Missing from the Suspended Plastic Sphere?

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SUMMARY

The discussion focuses on calculating the number of excess or deficit electrons in a small plastic sphere suspended between two parallel plates. The sphere has a mass of 2.60x10-15 kg and is subjected to a voltage of 265.4V, with a distance of 0.500 cm between the plates. The charge on the sphere was calculated to be 4.8x10-20 C, leading to a conclusion of 0.3 excess electrons. The confusion arose from the fractional value of electrons, which was clarified through a correction in the distance measurement.

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Homework Statement



A small plastic sphere is suspended between two parallel plates like so: http://gyazo.com/0b5425a78b645d85da0b3475d6d71734

How many excess or deficit electrons does the sphere have?

Homework Equations



##m=2.60x10^{-15}kg##
##V=265.4V ##
##d=0.500cm=0.000500m=5.0x10^{-4}m##
##g=9.81m/s^2##

##q = \frac{mgd}{V}##

##q = Ne##
##e = 1.6x10^{-19}C##

The Attempt at a Solution



The charge on the sphere is clearly positive because it is suspended in mid air and I calculated the magnitude of the charge to be ##q=4.8x10^{-20}C##.

This confused me slightly. Solving for the excess/deficit electrons ##N = 0.3##.

How can the sphere have a fraction of a deficit of electrons? I thought ##N## could only be an integer.
 
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Check your conversion of d to meters.
 
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gneill said:
Check your conversion of d to meters.

Whoops, I forgot a zero there ##d = 5.00x10^{-4}m##.

This doesn't really change the answer though.

EDIT : Ohhh I have an extra zero -facepalm-

I got it now thanks!
 
Zondrina said:
Whoops, I forgot a zero there ##d = 5.00x10^{-4}m##.

This doesn't really change the answer though.

EDIT : Ohhh I have an extra zero -facepalm-

I got it now thanks!

:smile:
 

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