How many energy requires to increase 1℃ of 1 liter of water using MICROWAVE?

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SUMMARY

This discussion focuses on the energy required to heat 1 liter of water by 1°C using a microwave for industrial purposes. The specific heat capacity of water is approximately 75.375 J/mol·K, leading to a requirement of 4187.5 joules to raise the temperature of 1 liter of water by 1°C. For a target increase of 33°C, a total of 138187.5 joules is necessary, which translates to a heating time of at least 275 seconds with a 500-watt microwave. The discussion also highlights energy losses in microwave generation and suggests alternatives like resistive heaters and heat pumps for improved efficiency.

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  • Understanding of specific heat capacity and thermal energy calculations
  • Familiarity with SI units and conversions
  • Knowledge of microwave power ratings and energy efficiency
  • Basic principles of thermal dynamics in heating systems
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  • Research the efficiency of resistive heaters compared to microwave heating
  • Explore the design and operation of heat pumps for industrial heating
  • Learn about energy loss mechanisms in microwave generators
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Engineers, industrial heating specialists, and anyone involved in optimizing energy use in heating processes will benefit from this discussion.

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we planning to heat water directly using microwave for industrial purpose. we need only 33deg Celsius for that I need this.
 
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It was 1 calorie per gram per deg C. Now in SI units...
Assume no phase change.
Specific heat capacity of water is about 75.375 ± 0.05 J/mol·K
The molecular weight is 18 and density is 1.00
So to increase the temperature of 18g = 18 ml of water 1°C takes 75.375 joule.

1 litre will require (1000 / 18 ) * 75.375 = 4187.5 joule per deg C.

A rise of 33°C will require 4187.5 * 33 = 138187.5 joule.
If your microwave generator delivers 500 watt that is 500 joule per second.
It will take 138187.5 / 500 = a minimum of 275 seconds to heat one litre 33°C.
 
The power that has to go into the water is simply the temperature difference multiplied by the thermal capacity of the water (4.2 J/(g*K)), for a temperature change of 1 K ("1℃") this is 4.2 J/g.

Other considerations: Microwaves lose about 50% of their energy in the generation of the microwaves. A simple resistive heater could save half the power and simplify the setup, and a heat pump could save even more power (but make it more complicated). Cooling the microwave generator with the water would be possible as well, and would improve the efficiency. Or cool something else if possible.
 

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