What is the Pattern of Number Combinations and Sums When Extracting Digits?

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The discussion focuses on generating two-digit numbers from unique three-digit combinations, emphasizing that each three-digit number can yield six distinct two-digit numbers. Participants reference permutations to explain the mathematical basis for counting these combinations. There is a need for clarification on how to handle cases where digits may repeat, particularly with the example of the number 111. The conversation also touches on the relationship between the number of permutations and the sums of the resulting two-digit numbers. Overall, the inquiry seeks to understand the patterns and commonalities in sums derived from these digit combinations.
Stef Pieterse
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Hi
If i have many 3 digit number which are all different and can not be zero,and have to make as many 2 digit numbers from each one of them. They all give me 6 different 2 digit numbers.
What pattern will this follow in general? And what will the sums of the 2 digit numbers have in common?

I hope you can help me, thank you very much
Regards
Stef
 
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If I understood your question you are referring to http://en.m.wikipedia.org/wiki/Permutation?wasRedirected=true" of n objects, given by the factorial n!=n*(n-1)*...*1.

However how do you want to count the 2-digit numbers extracted from the 3-digit 111? Would you still count 6 or just 1?

You have to clarify what do you want to know specifically for the sum of two 2-digit numbers as I didnt get your point.
 
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Suppose you have n digits and you are extracting r (=2 in your case) digits. Then nPr is the number of ways to get a r digited no.(since, all digits are different and nonzero). Then maximum of nCr different sums will be there and r! of the numbers will have a particular sum.
 
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