How Many Photons Does a 1-kW Radio Transmitter Emit at 880 kHz?

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A 1-kW radio transmitter operating at 880 kHz emits photons, and the energy of each photon can be calculated using the frequency. The relationship between power, energy, and time indicates that the transmitter uses 1 kW of energy per second. To find the number of photons emitted per second, one must first determine the energy of a single photon using the equation E = hf, where h is Planck's constant. By dividing the total energy output per second (1 kW) by the energy of one photon, the total number of photons emitted can be calculated. Clarification on the calculations and formulas is sought to ensure accuracy in determining the photon emission rate.
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a 1-kW raido transmitter operates at 880kHz. How many photons per second does it emit?

Power=work/time
Power=change in KE/time

f=1/T
T=1/880kHz

so 1 kw=change in KE/1.136x10^-6

change in KE=.00136 J

i don't know if i am doing this right. please point me in the right direction.


 
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You know the frequency (880kHz) of the photons and thus you can work out their energy with an equation you haven't written down. Then you know how much energy it uses per second (1 kW) and you can find the amount of photons per second from that?
 

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