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How many possibilities are there for the 3?

  1. May 31, 2009 #1
    1. The problem statement, all variables and given/known data
    Six digits from the numbers 2, 3, 4, 5, 6, 7, 8 are chosen and arranged in a row without replacement. Find the probability that the digits 2 and 3 appear in the proper order but not consecutively


    2. Relevant equations



    3. The attempt at a solution
    i know that the denominator is 7!, however i'm having trouble finding the numerator. I think that the numerator is 5C4 * 1 *1 however the answer is 5/21
     
  2. jcsd
  3. Jun 1, 2009 #2

    CompuChip

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    Re: Probability

    Suppose that 2 is in the 1st place. How many possibilities are there for the 3?
    If 2 is in the 2nd place, in how many places can you put 3?
    And if 2 is in the 3rd position?
    etc.
     
  4. Jun 2, 2009 #3
    Re: Probability

    i believe the answer is actually 5/14
     
  5. Jun 3, 2009 #4

    CompuChip

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    Re: Probability

    I got something else than 5/21 as well (5/14 sounds familiar). But we will know as soon as Jennifer posts again.

    Perhaps she has misquoted the answer, or didn't state the complete question.
     
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