How many possible 7-place license plates are there with 3 letters and 4 digits?

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SUMMARY

The problem of calculating the number of possible 7-place license plates consisting of 3 letters and 4 digits involves combinatorial mathematics. The correct approach is to first select the positions for the letters, which can be done in 7C3 ways, and then fill those positions with 26 possible letters, while the remaining positions can be filled with 10 possible digits. The total number of combinations is calculated as 7C3 * 26^3 * 10^4. The initial misunderstanding stemmed from treating letters and digits as indistinguishable, which is incorrect since repetition is allowed.

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  • Understanding of combinatorial mathematics, specifically combinations and permutations.
  • Familiarity with the concept of factorials and binomial coefficients (e.g., 7C3).
  • Knowledge of basic probability principles related to counting outcomes.
  • Ability to perform exponentiation for calculating possibilities (e.g., 26^3 and 10^4).
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  • Study combinatorial mathematics, focusing on combinations and permutations.
  • Learn about binomial coefficients and their applications in probability.
  • Practice problems involving counting principles and arrangements with repetition.
  • Explore advanced counting techniques, such as the inclusion-exclusion principle.
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iamjokerface
Hello,

I am stuck on this one problem. The problem asks:

How many different 7-place license plates are possible when 3 of the entries are letters and 4 are digits? Assume that repetition of letters and numbers is allowed and that there is no restriction on where the letters or numbers can be placed.

The way I approached the problem was:

There are 7C3 ways of choosing the places for letters, and in each letter place, there can be 26 choices. So 7C3*26*26*26 for the letters.
Then there are 7C4 ways of choosing the places for digits, and in each digit place, there are 10 choices, so 7C4*10*10*10*10.
To get the total possibilities, I multiplied the two.

I checked the answer but I am not getting the correct answer.

Where have I gone wrong?
 
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I think the problem is that letters are indistinguishable from one another, as are numbers. I would consider it more like this:

There 7 places to choose the first letter, 6 for the second, and 5 for the third. Once you've chosen the letter locations, the rest are all numbers. So I would probably have an expression like: $7\cdot 6\cdot 5\cdot 26^3 \cdot 10^4$. Does that work?
 

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