How many tanks can a 150 ft. barge carry without sinking more than 1 ft?

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A 150 ft. by 30 ft. barge is tasked with carrying 10-ton light tanks while limiting its submersion to an additional 1 ft. The buoyant force is calculated as approximately 1,248,779.7 N. Each light tank weighs about 88,964.4 N. To determine how many tanks can be loaded without exceeding the buoyant force, the total weight of the tanks must not surpass the calculated buoyant force. The discussion emphasizes the relationship between the weight of the tanks and the weight of the displaced water for stability.
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Homework Statement


A barge 150 ft. long and 30 ft. wide is to carry a payload of 10-ton light tanks over water. If the barge is to sink no more than an addictional 1 ft, how many tanks can be loaded?


Homework Equations





The Attempt at a Solution



Buoyant Force = fluid density x volume submerged x gravity
= (1 g/cm^3 x 1kg/1000g) x (4500 ft^3 x 28.317L/1ft^3 x 1000cm^3/1L) x 9.8 m/s^2
= 1,248,779.7 N

I've gotten this far and don't know what to do next. Also, this may be completely wrong.
 
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It might be easier to restate this as: "It receives an upthrust equal to the weight of water displaced."
Or the extra weight of cargo equals the weight of the water.
There no need to explicitly include g - especially if you can't decide which units to use.
 
NYCHE89: Nice work! Your equation and answer for buoyancy force, Fb, is correct. g = 9.807 m/s^2. Now, the weight of each light tank is Pt = 88 964.4 N. Therefore, see if you can now figure out how many light tanks would have a total weight not exceeding Fb. Try it.
 
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