How Many Volts Are Needed for My Motor to Lift 12kg in a Time-Lapse Project?

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SUMMARY

The discussion focuses on calculating the voltage required for a motor to lift a 12kg load (117N) vertically to a height of 1.3m over 60 minutes. The motor in question has a maximum voltage of 24V and a stall current of 1 Amp. The initial calculations presented were incorrect, as the work done should be calculated using the formula W=F·d, where F is the force and d is the distance. The correct work done is 1521J, leading to a power requirement of approximately 0.42W, which can be converted to voltage using the motor's specifications.

PREREQUISITES
  • Understanding of basic physics concepts such as work, power, and force.
  • Familiarity with the formula W=F·d for calculating work done.
  • Knowledge of electrical concepts, particularly voltage and current.
  • Experience with DC motors, specifically the specifications of the Dynamic Perception EZ-Swap DC Motor.
NEXT STEPS
  • Research the relationship between power, voltage, and current in DC motors.
  • Learn how to calculate work done using the formula W=F·d in practical applications.
  • Explore the specifications and performance characteristics of the Dynamic Perception EZ-Swap DC Motor.
  • Investigate methods for controlling motor speed and torque in time-lapse projects.
USEFUL FOR

This discussion is beneficial for engineers, hobbyists, and project managers involved in robotics, automation, or any application requiring precise motor control for lifting loads in time-lapse photography.

PC22
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I am working on a timelaps project so I need my motor to move very slowley, the motor I am using has a max voltage of 24V and a stall current of 1 Amp

The motor I want to use is on this link:
http://www.dynamicperception.com/EZ-Swap-DC-Motor-p/dp-dcm.htm

This motor will need to lift vertically 117N (12kg) of load to a height of1.3m (1300mm) in 60 mins (3600s) at a constant speed.

I need to find out the work done by the motor and convert it into Volts?

so far I have:

P=W/T

W=117N

T=0.36m/s

So: P=117/0.36 =325W I then times this by the time (3600s) to get the work done 1170000J

Is this correct ?
Can some out tell me how many volts this is ?

Any help would really be appreciated
 
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PC22 said:
This motor will need to lift vertically 117N (12kg) of load to a height of1.3m (1300mm) in 60 mins (3600s) at a constant speed.

I need to find out the work done by the motor and convert it into Volts?

so far I have:

P=W/T

W=117N

T=0.36m/s

So: P=117/0.36 =325W I then times this by the time (3600s) to get the work done 1170000J

Is this correct ?
That's incorrect.The work done can be found by W=F.d

Why did you write T as m/s?Isn't that the time taken(s)?or is it the constant speed given in the question?
And the W is not the force.Power =Work/time taken.
 
Care to help me work this out, please?
 

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