How Many Volts Are Needed for My Motor to Lift 12kg in a Time-Lapse Project?

In summary, the conversation is about finding the work done by a motor and converting it into volts. The motor needs to lift a load of 117N to a height of 1.3m in 60 minutes at a constant speed. The formula P=W/T is used to find the power, but it is incorrect. The correct formula is W=F.d. However, there is confusion about the units used for time (m/s or seconds) and the definition of power. Assistance is requested to clarify and solve the problem.
  • #1
PC22
6
0
I am working on a timelaps project so I need my motor to move very slowley, the motor I am using has a max voltage of 24V and a stall current of 1 Amp

The motor I want to use is on this link:
http://www.dynamicperception.com/EZ-Swap-DC-Motor-p/dp-dcm.htm

This motor will need to lift vertically 117N (12kg) of load to a height of1.3m (1300mm) in 60 mins (3600s) at a constant speed.

I need to find out the work done by the motor and convert it into Volts?

so far I have:

P=W/T

W=117N

T=0.36m/s

So: P=117/0.36 =325W I then times this by the time (3600s) to get the work done 1170000J

Is this correct ?
Can some out tell me how many volts this is ?

Any help would really be appreciated
 
Engineering news on Phys.org
  • #2
PC22 said:
This motor will need to lift vertically 117N (12kg) of load to a height of1.3m (1300mm) in 60 mins (3600s) at a constant speed.

I need to find out the work done by the motor and convert it into Volts?

so far I have:

P=W/T

W=117N

T=0.36m/s

So: P=117/0.36 =325W I then times this by the time (3600s) to get the work done 1170000J

Is this correct ?
That's incorrect.The work done can be found by W=F.d

Why did you write T as m/s?Isn't that the time taken(s)?or is it the constant speed given in the question?
And the W is not the force.Power =Work/time taken.
 
  • #3
Care to help me work this out, please?
 
Back
Top