How Many Ways Can You Roll Six Dice with Repeating Numbers?

  • Thread starter Thread starter ArcanaNoir
  • Start date Start date
  • Tags Tags
    Dice Probability
Click For Summary
SUMMARY

This discussion focuses on calculating the number of ways to roll six dice with specific conditions regarding repeating numbers. The participants explore the concepts of probability and combinatorics, particularly using negation to simplify the problem. Key calculations include determining the probability of rolling at least two, three, four, and five identical numbers, with specific formulas such as 6^6 - 6! for at least two identical numbers and arrangements for exactly four identical numbers using the formula 6!/(4!1!1!). The conversation emphasizes the importance of understanding permutations and combinations in solving these types of probability problems.

PREREQUISITES
  • Basic understanding of probability theory
  • Familiarity with permutations and combinations
  • Knowledge of factorial notation and its applications
  • Ability to apply negation in probability problems
NEXT STEPS
  • Study the concept of permutations in detail, focusing on formulas like nPr and nCr
  • Learn how to apply the principle of inclusion-exclusion in probability
  • Explore advanced probability topics, such as conditional probability and Bayes' theorem
  • Practice solving similar problems involving dice and other random variables
USEFUL FOR

Students studying probability, educators teaching combinatorial methods, and anyone interested in enhancing their understanding of statistical analysis in games of chance.

  • #61
Shouldn't the probability that all numbers are different plus exaclt 2 are alike and the rest different plus exactly three are alike plus...up to they are all the same be no greater than one?
 
Physics news on Phys.org
  • #62
ArcanaNoir said:
Shouldn't the probability that all numbers are different plus exaclt 2 are alike and the rest different plus exactly three are alike plus...up to they are all the same be no greater than one?

Correct, they should sum up to exactly one (or less than one depending on what you calculate exactly).
 
  • #63
Okay, I think I have this problem all done. I've solved it probably more than one way by now, and I got consistent answers. *runs away*
 
  • #64
ArcanaNoir said:

Homework Statement



How many ways can you roll six dice so that at least 2 numbers are the same? At least 3? At least 4? At least 5?

Homework Equations





The Attempt at a Solution



:cry: I've used every equation in the chapter and filled page after page with numbers all moved around. I'm drowning! Please help. I hate probability.

{at least two the same} = E2 + E3 + E4 + E5 + E6, where Ej = {exactly j the same} (and "+" denotes set union). E2 = {2 1s, others all different}+{2 2s, others all different}+... Clearly, all these have the same number of elements, so the number of elements in E2 is 6*|{2 1s, all others different}| (|{.}| = set cardinality). Now think of 6 bins and 6 balls tossed at random into them; we want the number of outcomes in which bin 1 has 2 balls and the others all have 0 or 1 ball each. This the type of thing for which the _multinomial_ distribution was designed.

RGV
 
  • #65
ArcanaNoir said:
*runs away*

Hey! Come back! :smile:
There's more...
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
6K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
23
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 16 ·
Replies
16
Views
3K
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
6K