How Many Ways to Seat a CEO and Vice Presidents Together at a Round Table?

In summary, there are (n+2)!/2 ways to seat the n members, including the CEO and 2 vice presidents, around a round table so that both vice presidents sit next to the CEO. This takes into account the CEO's seat being fixed, but does not consider the starting position of the CEO as being significant.
  • #1
MSG100
43
0
First of all, I would like to apologize for my bad english.

The Problem:

There is n members inclusive CEO and 2 vice presidents. In how many ways can they be seated around a table so that both vice presidents sits next to the CEO?Attempt at a solution:

There's in total (n+2)! ways to be seated at the table.

It should be divided by a vice president to the left (if his place are fixed). That gives us (n+1) opportunities. The same on the left hand side.

The other vice president only have one side to choose when the CEO and vice president are sat, (n).

All in all:

(2(n+2)!)/((n+1)(n))

Is this the right way to think?
 
Physics news on Phys.org
  • #2
It says 'inclusive', so there are only n altogether. You should not be getting an n+2 term.
I'm afraid I was not able to follow your reasoning from there.
You could go through these steps: how many ways to place the CEO? Now how many to place the VPs? Now how many to place everyone else?
 
  • #3
Ok, I don't think your alone not undertand what I just write:)
I need to do some more basic stuff about permutations and then come back to this problem.
 
  • #4
Your English is excellent except for the specific question of whether there are n people, with the CEO and vice presidents included, or whether there are n people plus the CEO and vice-presidents, making a total of n+ 2 people.

However many "other" people there are, I would start by seating the CEO. Since this is a round table with all seats equivalent, any seat will do. We then seat the two vice presidents beside the CEO. There are 2 ways to do this: calling one vice presidednt "A" and the other "B", "A on the CEO'S left and B on the right" or "A on the CEO's right and B on the left". Once we have seated them, we seat the remaining "m" (whether m= n or m= n--3) people- there are m! ways to do that.
 
  • #5
HallsofIvy said:
Your English is excellent except for the specific question of whether there are n people, with the CEO and vice presidents included, or whether there are n people plus the CEO and vice-presidents, making a total of n+ 2 people.

However many "other" people there are, I would start by seating the CEO. Since this is a round table with all seats equivalent, any seat will do. We then seat the two vice presidents beside the CEO. There are 2 ways to do this: calling one vice presidednt "A" and the other "B", "A on the CEO'S left and B on the right" or "A on the CEO's right and B on the left". Once we have seated them, we seat the remaining "m" (whether m= n or m= n--3) people- there are m! ways to do that.

There is a remaining issue, which is whether or not we regard all starting places of the CEO as equivalent, or whether we should multiply your suggested answer by n. One could argue either way; it depends on whether, for example, you regard the arrangements in which the CEO is in the northwest seat as being different from that where he/she is in the southeast seat, etc.
 

Related to How Many Ways to Seat a CEO and Vice Presidents Together at a Round Table?

What is the difference between permutations and combinations?

Permutations and combinations are both ways of arranging objects, but the main difference is that permutations take order into account while combinations do not. In other words, permutations are arrangements where the order matters, while combinations are arrangements where the order does not matter.

How do you calculate permutations?

To calculate permutations, you use the formula nPr = n! / (n - r)!, where n represents the total number of objects and r represents the number of objects being selected. This formula assumes that there are no repeated objects in the selection.

How do you calculate combinations?

To calculate combinations, you use the formula nCr = n! / (r! * (n - r)!), where n represents the total number of objects and r represents the number of objects being selected. This formula takes into account that order does not matter in combinations and assumes that there are no repeated objects in the selection.

What is the difference between with replacement and without replacement in permutations and combinations?

With replacement means that an object can be selected more than once, while without replacement means that an object can only be selected once. This affects the formulas used to calculate permutations and combinations, as well as the number of possible outcomes.

How are permutations and combinations used in real life?

Permutations and combinations are used in a variety of fields, including math, science, finance, and computer science. They are often used to solve problems involving arranging or selecting objects, such as in genetics, gambling, and data analysis. They can also be used to calculate probabilities and make predictions.

Similar threads

  • Precalculus Mathematics Homework Help
Replies
7
Views
2K
Replies
81
Views
5K
  • Precalculus Mathematics Homework Help
Replies
3
Views
2K
  • Set Theory, Logic, Probability, Statistics
Replies
20
Views
1K
  • Precalculus Mathematics Homework Help
Replies
1
Views
2K
  • Precalculus Mathematics Homework Help
Replies
2
Views
4K
  • Precalculus Mathematics Homework Help
Replies
9
Views
2K
  • General Math
Replies
1
Views
760
  • Set Theory, Logic, Probability, Statistics
Replies
2
Views
1K
  • Precalculus Mathematics Homework Help
Replies
1
Views
2K
Back
Top