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How may I derive this equation?

  • Thread starter staka
  • Start date
  • #1
23
0
How may I derive y=cos^3(sinx)?
I thought simply just y=3cos(sinx)^2(cosx)...

Answer given is -3cosxsin(sinx)cos^2(sinx) but no idea how to get to that.
 

Answers and Replies

  • #2
C.E
102
0
I am a bit confused about what the exact question is. What is it?
 
  • #3
23
0
How to derive the function: y=cos^3(sinx) is my question... solving for y'=.
 
  • #4
33,162
4,847
I think you didn't use the chain rule enough times.
You need the derivative of cos3(sin(x)) with respect to cos(sin(x)) times the derivative of cos(sin(x)) wrt sin(x) times the derivative of sin(x) wrt x.
 
  • #5
cristo
Staff Emeritus
Science Advisor
8,107
72
By derive you mean differentiate, right?

Try writing t=sinx, then y=[cos(t)]^3. Then, dy/dx=(dy/dt)(dt/dx). Course, you need to use the chain rule again when differentiating y wrt t.
 
  • #6
23
0
Alright. I'll retry.. solving.
 
  • #7
C.E
102
0
Oh, differentiate now I know what you are trying to do. Are you familiar with the chain rule?
 
  • #8
23
0
I am familar with the chain rule.. I'll retry.
 
  • #9
23
0
Alright thanks. I've solved it correctly.
 

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