How Much Charge Does the Second Charge Have?

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SUMMARY

The discussion focuses on calculating the charge of a second point charge based on the electric field produced by two charges. The first charge, located at the origin, has a value of 1.11 x 10^-5 C. The electric field at a distance of 9.11 m from the origin is measured at 1.59 x 10^3 N/C. The correct approach involves using the formula for the electric field due to a point charge, E = k*q/r^2, rather than the force equation. The calculated charge for the second charge is confirmed to be 2.44 x 10^-6 C.

PREREQUISITES
  • Understanding of Coulomb's Law
  • Familiarity with electric fields and their calculations
  • Knowledge of the constant k (Coulomb's constant) at 8.99 x 10^9 N m²/C²
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Review the derivation of the electric field formula E = k*q/r^2
  • Practice solving problems involving multiple point charges
  • Explore the concept of superposition in electric fields
  • Learn about the applications of electric fields in real-world scenarios
USEFUL FOR

Students studying physics, particularly those focusing on electromagnetism, as well as educators looking for problem-solving techniques in electric field calculations.

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Homework Statement


Two charges, one at the origin and one at x=1.6 m produce a field 1.59x10^3N/C at x = 9.11 m. The charge at the origin has a charge of 1.11 x 10^-5 C. How much charge does the second charge have?

http://books.google.com/books?id=vN...the origin has a magnitude of 845 N/C&f=false

Page 96 Question 3.49

Homework Equations



E=F/q
E=kq1q2/r^2
k=8.99x10^9


The Attempt at a Solution



I tried using coulomb's law to find Q2

1590=(9x10^9)(1.11x10^-5)(q2)/(9.11^2)

But my solution did not match the answer which was q2 = 2.44x10^-6C
 
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That's not the correct equation for the electric field due to a point charge. You have the equation for the force between two point charges. It's not really useful for this problem.
 
ah yes i got it ty
 

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