- #1

- 8

- 0

E= 4 N/C(i) + 5 N/C(j) + 6 N/C(k).

How much charge is enclosed by the box?

2. I believe I should be using Gauss's Law (Epsilon=permittivity of free space)

Ie= Q/Epsilon

Ie= ExA

Area=L^2

3. I basically multiplied all sides with its proper vector x area. The area for all sides seems to be the same since all L=2.54cm=.0254m.

Area came out to be 6.4516X10^-4 m^2.

I came out with a charge=Q=0

Not quite sure if I am calculating this correctly; please help.