# How much charge is enclosed by the box?

1. A box with a side of length L=2.54 cm is positioned with one of its corners at the origin of a rectangular coordinate system. There is a uniform electric field
E= 4 N/C(i) + 5 N/C(j) + 6 N/C(k).
How much charge is enclosed by the box?

2. I believe I should be using Gauss's Law (Epsilon=permittivity of free space)
Ie= Q/Epsilon
Ie= ExA
Area=L^2

3. I basically multiplied all sides with its proper vector x area. The area for all sides seems to be the same since all L=2.54cm=.0254m.
Area came out to be 6.4516X10^-4 m^2.
I came out with a charge=Q=0

haruspex