How Much Clamping Force to Prevent a Ball from Slipping in Robotic Grippers?

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To prevent the ball from slipping in robotic grippers, the static friction coefficient is 0.5, and the ball weighs 10 lb. The clamping force required is determined by analyzing the forces acting on the ball, including the normal and frictional forces. The grippers touch the ball at the midpoint, creating equal and opposite contact forces. The acceleration needed to keep the ball in circular motion is calculated, and the frictional force plays a crucial role in maintaining this motion. The solution involves resolving the forces into components and applying the appropriate equations to find the necessary clamping force.
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Homework Statement



The static friction coefficient between the grippers and the ball is 0.5, and the grippers
hold the ball such that they touch the middle of the ball on opposite sides.

Find the clamping force required to keep the ball from slipping out, if the ball weighs 10 lb.

us= 0.5
Mass of ball = 10 lb
gravity = 9.81 m/s^2

Angular velocity (wd) = 5 rad/s = Angular velocity of robot arm as they are attached.

Homework Equations


rc=4cos45 + 2sin45 = 4.243 ft
Motion of point C
Vc = (wr)(rc)
ar=\alpharc
an= wr^2 (rc)
ac= sqrt(ar^2 + an^2)

The Attempt at a Solution



Using the above equations and the givens I found the rc which I used along with wr to solve for Vc.

Vc = ( 5.0 rad/s) ( 4.243 ft) = 21.2 ft/s

Then solved for both components of acceleration where :

at= \alpha rc = 0
an= wr^2 x rc = 25 x 4.243ft = 106.07 ft/s^2

Then solved for magnitude which just equalled the normal acceleration

ac= 106.07 rad/s^2

Currently stuck on what to do for the second part of the question. I understand that I need to do a force FBD as I am given us and the mass of the ball. Noting that the pincers touch the middle of the ball on both sides, wouldn't that mean the contact forces oppose each other ( equal and opposite direction ) ?
 

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Cataracts said:
ac= 106.07 rad/s^2

Currently stuck on what to do for the second part of the question. I understand that I need to do a force FBD as I am given us and the mass of the ball. Noting that the pincers touch the middle of the ball on both sides, wouldn't that mean the contact forces oppose each other ( equal and opposite direction ) ?

Yes.

The sum of the forces acting on that ball must produce that acceleration, otherwise the ball isn't going to follow the circular path as you've assumed. The grip will be equal, opposite and perpendicular to that acceleration so that alone cannot produce that acceleration. But then there's the friction...
 
Last edited:
I realized that movement was only constrained in the j direction, therefore there was a k and i direction force of friction. I then gathered components in those directions and solved the system giving me the answer ! Thanks for the guidance !
 
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