How Much Coal Must Be Burned in a Steam Power Plant to Generate 900 MW?

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Homework Help Overview

The problem involves calculating the amount of coal required to generate 900 MW of power in a steam power plant, considering the efficiencies of two steam engines operating in sequence. The original poster presents the operating temperatures and the heat of combustion of coal, while also noting the efficiency of the engines as a fraction of the ideal Carnot efficiency.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the calculation of efficiencies for each engine and their implications for the overall system efficiency. There are questions about the relationship between power, work, and heat input, as well as the correct interpretation of efficiency in this context. Some participants express confusion regarding units and the nature of power versus work.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and attempting to clarify their understanding of the calculations involved. Some have provided guidance on how to relate the efficiencies of the engines to the total power output, while others are questioning their previous calculations and assumptions.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. There is also a noted discrepancy in temperature values that affects the efficiency calculations, leading to further discussion about the correct values to use.

  • #31
ok i get 12.8

what were you saying about the first one not taking into account that it was .65 Carnot efficiency because I don't see how this is so
 
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  • #32
ideasrule said:
I'm getting tired of pointing out careless mistakes.

In the first post you said the power plant puts out 900 MW of power. Alright, great. In post #17 you used 500 MW. In the answer in post #20, it's 600 MW. I mean, what the heck?

Also, I'm disappointed at the answer in post #20. It's wrong, period. They took into consideration the fact that the second engine is 0.65 times the Carnot efficiency, but didn't do the same for the first. I mean, what the heck?

i don't see how

e (Carnot) = 1 - 703.16 K/953.16 K = .2623
e = .65 e Carnot = .65(.2633) = .1705

what am I doing wrong
 
  • #33
Sorry, my mistake. Ignore that comment; the answer's correct.
 
  • #34
Wait so then...

I got e_system to be .0217
because I did

e_system = e_first intersection e_second = .1705(.1275) = .0217

now

e_system = |W|/|Q_H|

Therefore

|Q_H|= |W|/e_system
= (900 MJ)/.0217
= 4.147 E 10 J
what am I doing wrong now
 
  • #35
So I got the wrong input heat and don't see why...
 
  • #36
please anyone
 
  • #37
OH. So this is what's happening.

The first engine spits out some work, which is part of the electricity generated. It also spits out waste heat, which is used to power the second engine. I thought the first engine's work was used to power the second engine; in fact, it's the waste heat.
 
  • #38
so what do i do
 

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