How Much Energy Does a Linearly Declining Battery Voltage Deliver Over Time?

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The discussion focuses on calculating the energy delivered by a battery with a linear voltage decline from 1.5V to 1.0V over 40 hours while providing a constant current of 9mA. The user derived a power function and integrated it to find the energy delivered, resulting in 1622.6J. However, a discrepancy arose when comparing this calculation to the area under a graph of power versus time, which yielded only 324J. The issue was identified as an error in calculating the area under the graph, specifically only considering the triangular area rather than the entire shape. Accurate calculations and graph assessments are crucial for resolving such discrepancies.
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Homework Statement


A battery provides a continuous current of 9mA (.009A) for 40hrs (144,000sec). During that time the voltage drops from 1.5 to 1.0. Assume the drop is linear with time. How much energy does the battery deliver during this 40hr interval



Homework Equations


P=IV


The Attempt at a Solution


First I found an equation for voltage as a function of time (s) V(t)=1.5-3.472x10^-6t.
Then I figured power as a function of time P(t)=IxV(t)=.009(1.5-3.472x10^-6t)
P(t)=.0135-3.1x10^-8t. To find the energy delivered, I integrated P(t) so that E=.0135t-3.1x10^8t^2/2. The limits were from 0 to 144,000. I ended up with 1944-321.408=1622.6J
My problem is that when I just made a graph of power vs time and found the area under it from 0 to 144,000 I got 324J. Could I please get some guidance as to what I'm doing wrong?
 
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Check your graph.

ehild
 
Ok when I tried to find the area using the graph i only took the area of the triangle.
 
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