How Much Energy Is Released in Tritium Nucleus Formation?

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SUMMARY

The energy released during the formation of a tritium nucleus, composed of two neutrons and one proton, is calculated using the mass defect of 9.106 × 10–3 universal mass units. The correct energy release is approximately 8.48 × 10–2 MeV, derived from the equation E=mc2. Participants in the discussion emphasized the importance of unit conversion, particularly from Joules to Mega Electron Volts (MeV), clarifying that 1 MeV equals 1.6 × 10–13 Joules. Accurate mass units are essential for correct calculations.

PREREQUISITES
  • Understanding of nuclear physics concepts, specifically tritium formation
  • Familiarity with Einstein's mass-energy equivalence formula E=mc2
  • Knowledge of unit conversion between Joules and Mega Electron Volts (MeV)
  • Basic skills in handling mass units in nuclear reactions
NEXT STEPS
  • Research the process of nuclear fusion and its energy implications
  • Learn about unit conversions in particle physics, focusing on Joules to MeV
  • Explore the concept of mass defect and binding energy in nuclear physics
  • Study examples of energy calculations in nuclear reactions using E=mc2
USEFUL FOR

Students studying nuclear physics, educators teaching energy concepts in chemistry and physics, and researchers interested in nuclear fusion processes.

majormuss
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Homework Statement


A tritium nucleus is formed by combining two
neutrons and a proton. The mass of this nucleus
is 9.106 × 10–3 universal mass unit less than the
combined mass of the particles from which it is
formed. Approximately how much energy is
released when this nucleus is formed?
(1) 8.48 × 10–2 MeV (3) 8.48 MeV
(2) 2.73 MeV (4) 273 MeV


Homework Equations



E=mc^2

The Attempt at a Solution


I tried finding the energy by using what they gave me(9.106 × 10^-3) and fixing into the equation E=mc^2, but my anwser turns out 8.2 × 10^13( which obviously missing something)
 
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majormuss said:

Homework Statement


A tritium nucleus is formed by combining two
neutrons and a proton. The mass of this nucleus
is 9.106 × 10–3 universal mass unit less than the
combined mass of the particles from which it is
formed. Approximately how much energy is
released when this nucleus is formed?
(1) 8.48 × 10–2 MeV (3) 8.48 MeV
(2) 2.73 MeV (4) 273 MeV


Homework Equations



E=mc^2

The Attempt at a Solution


I tried finding the energy by using what they gave me(9.106 × 10^-3) and fixing into the equation E=mc^2, but my anwser turns out 8.2 × 10^13( which obviously missing something)

Think about what units you are using. You may need to convert units.
 


You can't just plug the numbers you have in and get the right answer because the units don't work out.
 


vela said:
You can't just plug the numbers you have in and get the right answer because the units don't work out.

so how do I change form Joules to Mega Electron Volts? do I multiply or divide by 1.6 *10^-19... that is where I tend to get confused.
 


Is a joule larger or smaller than a MeV?

So if I have 1 joule, should have 1*1.6*10^-13 MeV or 1/(1.6*10^-13) MeV? Which one gives a bigger answer?

Also, for mega electron volts the conversion factor is 1.6*10^-13 not -19, -19 is for electron volts.
 


majormuss said:
so how do I change form Joules to Mega Electron Volts? do I multiply or divide by 1.6 *10^-19... that is where I tend to get confused.

You also need the mass units to be right.
 

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