How Much Energy Is Released in Tritium Nucleus Formation?

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majormuss
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Homework Statement


A tritium nucleus is formed by combining two
neutrons and a proton. The mass of this nucleus
is 9.106 × 10–3 universal mass unit less than the
combined mass of the particles from which it is
formed. Approximately how much energy is
released when this nucleus is formed?
(1) 8.48 × 10–2 MeV (3) 8.48 MeV
(2) 2.73 MeV (4) 273 MeV


Homework Equations



E=mc^2

The Attempt at a Solution


I tried finding the energy by using what they gave me(9.106 × 10^-3) and fixing into the equation E=mc^2, but my anwser turns out 8.2 × 10^13( which obviously missing something)
 
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majormuss said:

Homework Statement


A tritium nucleus is formed by combining two
neutrons and a proton. The mass of this nucleus
is 9.106 × 10–3 universal mass unit less than the
combined mass of the particles from which it is
formed. Approximately how much energy is
released when this nucleus is formed?
(1) 8.48 × 10–2 MeV (3) 8.48 MeV
(2) 2.73 MeV (4) 273 MeV


Homework Equations



E=mc^2

The Attempt at a Solution


I tried finding the energy by using what they gave me(9.106 × 10^-3) and fixing into the equation E=mc^2, but my anwser turns out 8.2 × 10^13( which obviously missing something)

Think about what units you are using. You may need to convert units.
 


You can't just plug the numbers you have in and get the right answer because the units don't work out.
 


vela said:
You can't just plug the numbers you have in and get the right answer because the units don't work out.

so how do I change form Joules to Mega Electron Volts? do I multiply or divide by 1.6 *10^-19... that is where I tend to get confused.
 


Is a joule larger or smaller than a MeV?

So if I have 1 joule, should have 1*1.6*10^-13 MeV or 1/(1.6*10^-13) MeV? Which one gives a bigger answer?

Also, for mega electron volts the conversion factor is 1.6*10^-13 not -19, -19 is for electron volts.
 


majormuss said:
so how do I change form Joules to Mega Electron Volts? do I multiply or divide by 1.6 *10^-19... that is where I tend to get confused.

You also need the mass units to be right.