How Much Energy Would a Meteorite Impact Release Compared to an Atomic Bomb?

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The discussion revolves around calculating the kinetic energy of a meteorite that impacted Earth, specifically one that was observed in 1972. Participants emphasize using the kinetic energy formula E = 1/2mv^2 to find the energy in joules before the impact. The conversation includes converting this energy into megatons of TNT to compare it with atomic bomb explosions, including the Hiroshima bomb's energy equivalent. There are reminders about forum guidelines against posting nearly complete answers to encourage learning. The focus remains on understanding the calculations and their implications regarding energy release from meteorite impacts compared to nuclear explosions.
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Homework Statement



On August 10, 1972, a large meteorite skipped across the atmosphere above western United States and Canada, much like a stone skipped across water. The accompanying fireball was so bright that it could be seen in the daytime sky (Fig. 7-24). The meteorite's mass was about 4 x 10^6 kg. Its speed was about 15 km/s. Had it entered the atmosphere vertically, it would have hit the Earth's surface with about the same speed.

hrw6_7-24.jpg


(a) Calculate the meteorite's loss of kinetic energy (in joules) that would have been associated with the vertical impact.
J
(b) Express the energy as a multiple of the explosive energy of 1 megaton of TNT, which is 4.2 1015 J.
megaton TNT
(c) The energy associated with the atomic bomb explosion over Hiroshima was equivalent to 13 kilotons of TNT. To how many "Hiroshima bombs" would the meteorite impact have been equivalent?

Homework Equations



I'm pretty confused on how to start this one, I guess this unit I have been pretty lost the whole unit. So if someone could give me a good way of starting I would greatly appreciate it.
 
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What is the equation for the Kinetic Energy (KE) of a mass m moving with a velocity v? What happens to the KE when the mass is stopped suddenly like in an impact on the surface of the Earth?
 
berkeman said:
What is the equation for the Kinetic Energy (KE) of a mass m moving with a velocity v? What happens to the KE when the mass is stopped suddenly like in an impact on the surface of the Earth?

E = 1/2mv^2

Kinetic energy goes to 0 when it hits the surface, correct?
 
Kildars said:
E = 1/2mv^2

Kinetic energy goes to 0 when it hits the surface, correct?

Yep. Now calculate the KE of the meteorite in joules (1J = 1kg*m/s^2), and do the math for the problem. I'm kind of interested in that last answer myself.
 
berkeman said:
Yep. Now calculate the KE of the meteorite in joules (1J = 1kg*m/s^2), and do the math for the problem. I'm kind of interested in that last answer myself.

/confused.
 
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Kildars said:
/confused.

What is the KE of the meteorite before the impact (use that equation), expressed in joules like the problem statement says?
 
Find initial KE with KE=\frac{1}{2}mv^2. This answer, assuming you use kilograms for mass and meters/second for velocity, is in Joules. Convert from Joules to Megatons by << rest of complete answer deleted by berkeman >>
 
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americanforest said:
Find initial KE with KE=\frac{1}{2}mv^2. This answer, assuming you use kilograms for mass and meters/second for velocity, is in Joules. Convert from Joules to Megatons by << rest of complete answer deleted by berkeman >>

Please do not post almost-complete answers to homework questions. It is against forum guidelines, and does not help the student to learn anything.
 
berkeman said:
Please do not post almost-complete answers to homework questions. It is against forum guidelines, and does not help the student to learn anything.

Sorry. Won't happen again. :redface:
 
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americanforest said:
Sorry. Won't happen again. :redface:

Fair enough. And thanks for helping out with homework questions. The more people helping, the better.
 
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