How Much Force to Pull a 1 Tonne Rock Up a 30 Degree Slope?

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Discussion Overview

The discussion revolves around calculating the minimum force required to pull a 1 tonne rock up a 30-degree slope, considering the gravitational force and resistance due to friction. Participants explore the forces acting on the rock, including gravity, normal force, friction, and the pulling force from a pulley system.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant states that the weight of the rock is 9800N, calculated from its mass (1 tonne = 1000kg) multiplied by the acceleration due to gravity (9.8 m/s²).
  • Another participant corrects the first by noting that 9800N represents the gravitational force acting on the rock, not the total force needed to move it up the slope.
  • Participants mention the need to consider multiple forces acting on the rock, including gravity, normal force, friction (350N), and the force exerted by the pulley system.
  • A suggestion is made to set up a free body diagram to visualize the forces acting on the rock.

Areas of Agreement / Disagreement

Participants generally agree on the need to account for various forces acting on the rock, but there is no consensus on the calculation of the minimum force required, as the discussion remains unresolved.

Contextual Notes

There are unresolved mathematical steps regarding how to combine the forces acting on the rock to determine the minimum pulling force needed.

vbillej
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1. A 1 tonne rock is being dragged up a 30 degree slope using the a pulley system.
If there is a constant resistance to movement between the rock and the ground of 350N, calculate the minimum force necessary to drag the rock up the slope.



2.



3. All i got so far is

1t = 1000kg

1000kg x 9.8 (gravity)
=9800N
Acting upon the slope from the rock
 
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Set up a free body diagram to find the forces acting on the rock.

Thanks
Matt
 
Hi vbillej! :smile:
vbillej said:
3. All i got so far is

1t = 1000kg

1000kg x 9.8 (gravity)
=9800N
Acting upon the slope from the rock

No, that's wrong …

9800N is the force of gravity on the rock.

There are four forces on the rock … gravity, normal force, friction force (= 350N), and the force from the rope.

As CFDFEAGURU :smile: says, set up a free body diagram.
 
Thanks both of you for your replies

tiny-tim said:
Hi vbillej! :smile:

9800N is the force of gravity on the rock.

.

Yes i forgot its actually the weight from the rock, thanks for reminding me
 

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