- #1
justinh8
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1. Homework Statement
Jane, mass of 55kg holds one end of a vertical rope that passes up over smooth rock and down along a 30 degrees sloping hill as shown. But Josh, mass of 95kg tightly holds the other end of the rope. Assume no friction. Calculate the acceleration. The picture is included
Fjane = m x g = 55 x 9.81 = 539.5 N
Fjosh = m x g = 95 x 9.81 x sin 30 degrees = 466 N
I know what to do from here but my main question is, will jane go up or will she go down??
According to the forces of gravity jane will go down, right? But the heavier mass belongs to Josh.
If Jane was to get pulled up than the equations would be:
1.T(tension) - mjane(9.81) = mjane x acceleration
2.mjosh x sin(30) - T(tension) = mjosh x acceleration
Is that correct?
if it is i end up with -0.5m/s^2
However, I am not sure if its right please correct me
Jane, mass of 55kg holds one end of a vertical rope that passes up over smooth rock and down along a 30 degrees sloping hill as shown. But Josh, mass of 95kg tightly holds the other end of the rope. Assume no friction. Calculate the acceleration. The picture is included
The Attempt at a Solution
Fjane = m x g = 55 x 9.81 = 539.5 N
Fjosh = m x g = 95 x 9.81 x sin 30 degrees = 466 N
I know what to do from here but my main question is, will jane go up or will she go down??
According to the forces of gravity jane will go down, right? But the heavier mass belongs to Josh.
If Jane was to get pulled up than the equations would be:
1.T(tension) - mjane(9.81) = mjane x acceleration
2.mjosh x sin(30) - T(tension) = mjosh x acceleration
Is that correct?
if it is i end up with -0.5m/s^2
However, I am not sure if its right please correct me