# How much heat ΔQ is consumed to raise the ice temperature

1. How much heat ΔQ is consumed to raise the ice temperature from Ti = -20 Celsius to meltingpoint Tf = 0 ? how long does it take ?

2. dQ/dt = H = 300 W

dQ = cmΔT

3 I got it to be 2.49 * 10^-21 J. Is it right ?

Andrew Mason
Homework Helper

1. How much heat ΔQ is consumed to raise the ice temperature from Ti = -20 Celsius to meltingpoint Tf = 0 ? how long does it take ?

2. dQ/dt = H = 300 W

dQ = cmΔT

3 I got it to be 2.49 * 10^-21 J. Is it right ?
You will have to provide a bit more information. How much ice are we talking about? Does the heat source provide 300 W?

AM

I dont know anything about the mass.

c = 1/m * dQ/dt (1)

c = 4190 kJ/kg (heat capacity of water)

Q = mcΔT (2)

From equation (1): m = (dQ/dt)/c (3)

m = 300W/4190 k//kg = 0.0715 kg

(2) Q = (0.0715 kg)(4190 kJ/kg)(273-15-253.15)K <==>

Q = 5.99 =~ 6 J

t = Q/H (4) (heat/power)

t(time) = 6.0 J/300 W = 0.02 J/s = 2 min

Is it right ?

How did you get the equation (1)?

I just solved it, an oversight

Andrew Mason