How much heat in joules must be added to 0.841 kg of aluminu

[Alice7979]

Homework Statement

How much heat in joules must be added to 0.841 kg of aluminum to change it from a solid at 130 °C to a liquid at 660 °C (its melting point)? The latent heat of fusion for aluminum is 4.0 x 105 J/kg.

Homework Equations

Q = mL
Total = mc∆t + mL = m(c∆t +l)

The Attempt at a Solution

i think it is it .841(.9(660-130) + 4*105) but the answer i get isn't right

 

[Nathanael]

The Attempt at a Solution

i think it is it .841(.9(660-130) + 4*105) but the answer i get isn't right

That 0.9, the specific heat of aluminum, is not in standard units. It’s 0.9 kilojoules / kg (or equivalently, 0.9 J / g) and not 0.9 J / kg

 

[Chestermiller]

Also, that heat of fusion should be 400000 J/kg (actually 321000 J/kg according to an internet source).

 

[Nathanael]

Also, that heat of fusion should be 400000 J/kg (actually 321000 J/kg according to an internet source).

I thought it was weird to say 4*105 hahaha 10^5 makes a lot more sense

 

[Alice7979]

That 0.9, the specific heat of aluminum, is not in standard units. It’s 0.9 kilojoules / kg (or equivalently, 0.9 J / g) and not 0.9 J / kg

I thought it was weird to say 4*105 hahaha 10^5 makes a lot more sense

Yea I didn't realize it changed it to that.