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How many pounds of pressure are exerted by a gallon of freezing water?
The discussion revolves around the pressure exerted by a gallon of freezing water, particularly focusing on the relationship between temperature, pressure, and the phase transition from liquid to solid. The scope includes theoretical considerations and implications of pressure in confined systems.
Participants express varying interpretations of the pressure-temperature relationship in the freezing process, with no consensus reached on the exact pressure exerted by a gallon of freezing water or the implications of the calculations presented.
The discussion includes assumptions about the conditions of the system, such as the nature of confinement and the specific weights applied, which may influence the freezing point and pressure calculations.
Originally posted by Bystander
How much would you like it to be? Pressure along the liquid-solid coexistence line is independent of volume; it depends only upon the temperature at which you establish the liquid-solid equilibrium. The liquid-solid coexistence begins at the triple point of water, 273.16 K and x Pa, proceeds to lower temperatures and higher pressures, 273.15 K and 0.1 MPa (ordinary freezing pt.), and goes wandering off through a fascinating phase diagram. At near normal conditions, you can figure something like 10 MPa/K for water in confined vessels --- once you cool to a point at which the pressure equals the burst or deformation limit for the vessel, the water freezes and the vessel bursts or deforms to accommodate the larger volume of the solid.