(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A vessel whose walls are thermally insulated contains 2.40kg of water and 0.450kg of ice, all at a temperature of 0.0 C. The outlet of a tube leading from a boiler in which water is boiling at atmospheric pressure is inserted into the water. How many grams of steam must condense inside the vessel (also at atmospheric pressure) to raise the temperature of the system to 28.0 C? you can ignore the heat transferred to the container.

2. Relevant equations

Q=mc∆t

Q=mL

Water heat of fusion - 334000

Water heat of vaporization - 2256000

specific heat of water - 4190

3. The attempt at a solution

I am pretty sure my logic is right but my answer does not match with the book answer. I think the book may be wrong... The answer in the book is 190g.

What I did was:

Q(melting ice) + Q(water + melted ice from 0 C to 28 C) = Q(vaporization)

(0.45kg)(334000) + (0.45kg+2.4kg)(4190)(28K) = m(2256000)

I solved for m and I get 214.8g.

Am I doing anything wrong? If so what?

Thanks.

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# Homework Help: How much steam to raise vessel temperature from 0 to 28 C?

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