A copper calorimeter can with mass 0.466kg contains 00950kg of ice. The system is initially at 0.0C. If 0.0350kg of steam at 100C and 1atm pressure is added to the can, what is the final temperature of the calorimeter can and its contents?
The Attempt at a Solution
I am going to assume all the ice melts and all the steam boils. If my answer is between 0C and 100C then I know that this is true. If it is below 0C or above 100C I will have to solve it differently.
Thus we have
-->Q(copper) + Q(ice melt) + Q(water warming) = Q(steam condensing) + Q(water cooling)
-->(0.446kg)(390)(Tf-0) + (0.095kg)(334000) + (0.095kg)(4190)(Tf-0) = (0.035)(2256000) + (0.035)(4190)(Tf-100)
When I solve this I get 76.6C, however the answer is 86.1C.
What am I doing wrong?