How Much Work Does Gravity Do on an Ice Flake in a Bowl?

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Homework Help Overview

The problem involves calculating the work done by gravity on a 2.00 g ice flake released from the edge of a hemispherical bowl with a radius of 22.0 cm. The context is centered around gravitational forces and work done in a physics setting.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the appropriate use of gravitational acceleration and the calculation of distance in the context of the problem. Questions are raised about the vertical distance the ice flake falls and the relationship between the height and the radius of the bowl.

Discussion Status

The discussion is ongoing, with participants providing insights into the relationship between the height of the bowl and the gravitational force. Some guidance has been offered regarding the use of the equation for work done, but no consensus has been reached on the specific calculations.

Contextual Notes

Participants note that the height the ice flake travels is equal to the radius of the hemispherical bowl, which is a key assumption in the problem. There is an emphasis on understanding the geometry of the situation without resolving the calculations.

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Homework Statement



a 2.00 g ice flake is released from the edge of a hemispherical bowl whose radius is 22.0 cm. the Flake-bowl contact is frictionless. How much work is done on the flake by the gravitational force during the flake's descent to the bottom of the bowl?

Homework Equations



w=fd

The Attempt at a Solution



do i use 9.81 m/s^2 as the force?
and how do i know the distance?
 
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If you were sitting on the edge of a cereal bowl and you slid down to the bottom of the bowl how far vertically would you have fallen? You've been given that.

9.8 m/s^2 is the acceleration of gravity. You need a force, mass * acceleration.

Then you've got the only equation you needed.
 


What is the distance between the bottom of the hemisphere and the top of the hemisphere?
 


Hopefully this helps, it's not too complicated so don't over think it.
 

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Kabbotta said:
Hopefully this helps, it's not too complicated so don't over think it.

I was asking you. The hemisphere is half of a sphere, so the center to any point on the surface is a radius, so what is the height of the sphere?

(By height, I mean the vertical distance the ice flake travels to the bottom of the sphere)
 


The snowflake starts at the edge of a hemispherical bowl so the height is equal to the radius.

In your case,
W = mgr

If there was a full sphere, the height from top to bottom would be the diameter or 2*radius.
 


rock.freak667 said:
What is the distance between the bottom of the hemisphere and the top of the hemisphere?

This height is equal to the radius of the hemispherical bowl that is directly given in the question. So in this case,

W = mgr
 


Kabbotta said:
This height is equal to the radius of the hemispherical bowl that is directly given in the question. So in this case,

W = mgr

I apologize, I did not see your post before mine. But I was not asking for my clarity, I was asking the OP.
 


Oh, I see, your post makes a lot more sense now ; )
No problem.
 

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