Consider the vessel. It is filled to a depth of 1 foot of water. Write an integral in terms of y (the distance from the bottom) for the work required to pump all the water to the top of the vessel. Water weights 62.4 lbs/ft3. Relevant Equations W = ∫F dx Pressure = density * g * depth F = Pressure * V Attempt P = 62.4 * 9.8 * y = 611.52y Based on similar triangles, I was able to get a width of (3/2)y. Thus, the volume becomes: V = 5*(3/2)y*Δy = 7.5yΔy So the force is F = (611.52y)(7.5y)Δy I stopped here because I wasn't sure about my work. Any help?