- #1
think4432
- 62
- 0
1. A tank is formed by revolving y = 3x^2, x = [0,2] around the y-axis is filled to the 4 feet point with water (w = 62.4 lb/ft^3). Find the work necessary to pump the water out of the tank over the top.
I got the integral being from a = 0 and b = 4 and integrating [(12y-y^2)/3]dy with w and pi as constants outside of the integral.
And after the integration I got:
224/9 pi (62.4)
And when I multiplied the 62.4 out it came out to be 1553.066 pi
Would this be correct? Just seems bit of a weird number?
[I asked this question earlier...and received help on it on an earlier thread, but I just wanted to see if the numbers I got are correct]
I got the integral being from a = 0 and b = 4 and integrating [(12y-y^2)/3]dy with w and pi as constants outside of the integral.
And after the integration I got:
224/9 pi (62.4)
And when I multiplied the 62.4 out it came out to be 1553.066 pi
Would this be correct? Just seems bit of a weird number?
[I asked this question earlier...and received help on it on an earlier thread, but I just wanted to see if the numbers I got are correct]