How to calcoulate force applied?

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Homework Help Overview

The problem involves calculating the force required to roll a 30 kg metal block across a floor with a given coefficient of friction. The original poster seeks to determine the applied force, normal force, frictional force, and work done while maintaining uniform speed.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the implications of uniform speed and the need for a free body diagram. Questions arise regarding the terminology used, such as "weight of force," and the relationship between applied force and frictional force.

Discussion Status

Some participants have provided guidance on the relationship between forces for uniform motion and the importance of drawing a free body diagram. There is an ongoing exploration of the definitions and calculations involved, with no explicit consensus reached yet.

Contextual Notes

Participants are working under the constraints of the problem statement and the need to clarify terms and relationships between forces without providing complete solutions.

jamesblim168
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Homework Statement


if the coefficient of friction between a 30 kg metal block and the floor is 0.16, what force is required to roll this block across the floor at a uniform speed? how much work is done? find : weight of force, normal force, force applied and fricitional force

Homework Equations


fn=mg
Ff=UxFn

The Attempt at a Solution

so far i only got this
weight of force = 294
normal force =294
frictional force = 47.04

How do i get force applied?
 
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Uniform speed implies zero acceleration. Have you drawn a free body diagram?
What does 'weight of force' mean? Given your numbers, I think you mean the gravitational force on the object.
 
to get uniform motion you need to make the net force on the body equal 0
 
Draw the free body diagram. To move the block the applied force has to be greater than or equal to the oposing frictional force. If it's greater than the frictional force the block will accelerate. The problem states it's "uniform speed" so it's not accelerating. Leading to the obvious answer.

As for "How much work is done" remember that

Work = force * distance
 

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